The area of an isosceles triangle is determined by:Įxample 4: Find the area of a triangle whose sides are 8, 9 and 11 respectively. If two sides and the angle between them are given then the area of the triangle can be determined using the following formula:Įxample 1: Find the area of a triangle whose base is 14 cm and height is 10 cm.Įxample 2: Find the area of a triangle whose sides and the angle between them are given as following:Īrea = ½ × 5 ×7 × 0.707 (since sin 45 ° = 0.707)Įxample 3: Find the area (in m 2) of an isosceles triangle, whose sides are 10 m and the base is12 m. In the figure shown above the area is thus given as: ½ × AC × BD.Īdditional formulas for determining the area of a triangle:Īrea of a triangle = √(s(s-a)(s-b)(s-c)) by Heron's Formula (or Hero's Formula), where a, b and c are the lengths of the sides of the triangle, and s = ½ ( a + b + c) is the semi-perimeter of the triangle.Ī= ½ × Product of the sides containing the right angle. Then, the length of the perpendicular line from the opposite vertex is taken as the corresponding height or altitude. In the figure alongside of the ΔABC, the perimeter is the sum of AB + BC + AC.Īny side of the triangle may be considered as its base. The perimeter of a triangle = Sum of three sides An obtuse-angled triangle has one angle greater than 90°.An acute-angled triangle has all angles less than 90°.A right-angled triangle has one right angle (90°).
A triangle is a polygon which has three sides and can be categorized into the follow types:
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